Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $3x^{2} - 18x + 27 = 0$.

(A) The given quadratic equation is $3x^{2} - 18x + 27 = 0$.
Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 3$,$b = -18$,and $c = 27$.
The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.
Substituting the values: $D = (-18)^{2} - 4(3)(27)$.
$D = 324 - 324 = 0$.
Since the discriminant $D = 0$,the roots of the quadratic equation are real,rational,and equal.